[Youtube Review][Veritasium] Beaker Ball Balance Problem

(Recommended)Popular Videos : [Veritasium] Beaker Ball Balance Problem

 

This time, I will review the popular YouTube videos.

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To save your busy time, why don't you check out the fun contents, summary, and empathy comments of popular YouTube videos first and watch YouTube?

(Recommended)Popular Videos : [Veritasium] Beaker Ball Balance Problem

https://www.youtube.com/watch?v=QD3hbVG1yxM

 

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Playtime Comments : [Veritasium] Beaker Ball Balance Problem

Aq***:

0:29 , white one will weight less because it is pulling the weight upwards while the blue ball pulls it downwards? nah?  or it could be that the blue ball is lighter specifically because it is being pulled up  bu I am going with the one that the white one will be lighter and the blue one will be heavier.

 

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Top Comments : [Veritasium] Beaker Ball Balance Problem

Pi*********:

Dude you've done this twice already with the same experiment. I want to find what's gonna happen.

Kn**********************:

I was sure it was going to stay balanced, I even convinced myself that I knew exactly why. Laws of physics are tricky.

pe********:

"You can make your selection by clicking one of the on-screen annotations."

No you can't.

Yo*******************************:

Wow I'm so naive, I've just heard veratasiam's slogan which is "element of truth" and in italian the "vero" means right or true. Can't believe I've never made this simple connection

Jo********:

Both beakers contain the same volume. the one on the left is a closed system, the buoyancy is balanced within the beaker so it has only the same effect as if the pingpong ball was just sitting beside the beaker on the balance. The right side, the water is providing some buoyancy to the ball, and the ball is part of an external system, so the right side will experience a downward force equal to some water of the volume of the ball. That's more than the weight of the pingpong ball. The right side will go down.

Vi*********:

I betcha it's right, but I'm still guessing left

Ar*************:

I must say, I take a strange pleasure in seeing (what I assume are) engineering students struggling with a physics problem

Nu*************:

may i know where can i watch the continuation of this vid?

Jo*******:

Acrylic ball side would go down since the water on this side will try to go to a more 'bulk' state which means it would push that acrylic ball up, the reaction being the beaker goes down.

sp******:

Usually a dense object will tend to sink in a less dense static fluid. In this case the acrylic ball is static but once the balance is released, the water isn't static anymore. Considering both beakers in a balanced system (no fight against gravity or archimides), the one on the right will go up, but not because of the weight of the ping pong ball, but because the water on the right will wanna push the acrylic ball down. just my thought, (maybe what i said is just stupid).

Ma******:

Damn it! I need the answer!

Ni***********:

Acrylic annotation link is broken @ end of video

Ed******:

I think the right hand side will fall until the heavy ball is only very slightly submerged in the water. The upward force on the ball from the string is equal to the weight of the ball minus the buoyancy force from the water. It is as if it's suspending the same ball in air but with a density of 1000 kg/m3 less than the ball in the water. The right hand side will drop because the difference between the weight of the ball and the weight supported by the string is the same as the weight of a ball of water the same size. Therefore the weight of the right hand side is equal to the weight of water plus the weight of a sphere of water the same size as the ball, which is heavier than the sum of the water and ping pong ball on the left hand side.

Ja******:

The side with the acrylic ball will go down (supposing the scales are functioning correctly, without much friction etc.).

The acrylic ball itself will pretty much remain suspended at the same height, thanks to the thread, but the ball exerts a downwards-pointing force opposite to the buoyancy. That force is equal to the weight of the displaced water, and thus stronger than the weight of the pingpong ball on the other side. If the pingpong ball had exactly the same density as water, the scales wouldn't move.

IL*********:

I'm going to take a stab at explaining it before watching the other video.
The ping-pong ball, due to being filled with air, basically has the effect of removing its own volume's worth of water from the beaker.
The acrylic ball, though it is independently suspended, is still also suspended in the water. Imagine if you were holding the string of the acrylic ball and you lowered it into the water. You would feel the decrease in weight.
Therefore, my prediction is the ping-pong side goes up.

Th******************:

The remaining balanced due equal displacement argument makes the most sense to me, since displacement only depends on volume and not mass, and both balls displace the same volume.

Fa*****************:

I think it will stay balanced. Same amount of same dense liquid, and same Archimedes forces on two balls(because height and density of liquid is equal) will cause to same weight

Th*********:

Oh man, this is a tricky one. I'm guessing the one with the blue ball with sink since the weigh of the water increases with the ball inside...? Bah, I'll just wait for the answer.

Ma****:

If you think about it, there is no external force on the pingpong ball, so it should weigh exactly the same amount as a floating pingpong ball. Now you can apply archimedes principle with an imagined floating pingpong ball vs the blue ball. And it turns out that the blue ball displaces more water.

sm*******:

If the water is displaced on both sides equally there will be no change.
The suspended ball displaces the same amount of water as the tethered ping pong ball... There will be no change. If one is slighter greater than the other it will tilt to that side... But that would be an error :)

Mi*********:

My prediction will be... since the water displacement is equal in both beakers, it should remain balanced on the scale.  Let's see who's correct, and why that is the case!   @Veritasium 

Gr*********:

The pong ball will sink slowly, that jug has the mass of the liquid plus the mass of the ball. The other side has just the mass of the liquid.

Sl**:

Woohoo another video from the prettiest youtuber alive, Derk.

Si**********:

Damn it vessel is screwing with me, I get deja vu at the beginning of some videos now before realizing I've seen them already

La************:

I really enjoy the "Choose your answer" videos.  It makes me really consider, instead of passively consuming.

Cu********:

The ping-pong ball is trying to float, so it will pull from the bottom while displacing the same amount of water.

Sh************:

there is one more possibility , I can make the white ball(less denser) tilt down if mp*g > ma*g-T where mp(mass of white ball) , ma(mass of blue ball)

Ab***************:

The ping pong ball will go down because the other ball is being lift up, therefore it's not applying any mass to the scale, where as the Ping pong ball is tied to the beaker and although it a lower density than water it's still applying mass to the scale

bi*****:

balanced, because the buoyancy of the ping pong ball is relative to the beaker itself. this would be like pulling your own hair and flying.
and the acrylic ball isn't supported by the beaker so it does not contribute to the apparent weight of the liquid.
so both the liquids cover the same amount of space because the balls are sized the same, so all of the variables should* be the same.

PV************:

I tell that the ping pong ball container goes down due to the extra mass of the ping pong ball in the system; where as in the other case the acrylic ball is not a part of the system and the tension force does not cancel out as in the case of ping pong ball .

Ch************:

I just discovered this experiment/video.  My explanation seems a bit more straight forward.  The water and beakers are the same mass - it doesn't matter about the displacement of the water unless the water spills out - they are equal on both sides so they can be ignored. The blue ball is not interacting at all with the beaker/water It is not transferring it's mass to the beaker so it has no effect on the weight on that side of the balance.  - you could just leave that out of the setup without any change. The white ball has an upward buoyant force which is directly applied to the beaker making that side of the system weigh less.  Similar to weighing something and lifting some of the weight - the overall weight of the system goes down. Thoughts? (and don't be rude)

Ji*******:

I think the system will cause the ping pong side to fall. The buoyancy acting on the two balls is the same, the only net force on the system is from the added mass of the pingpong ball. The acrylic ball has its mass suspended so that will cause no net force.

Ki*************:

Any force from the ping pong ball's mass is countered by the ball trying to pull the tethered beaker up. I predict the ping pong side will rotate down too the point where the acrylic ball is about to breach the water surface.

Ma********:

It will go up and down

Be******:

I would guess that since both balls are being artificially neutrally suspended in the water, and that a sea-fairing vessel's mass is determined by the volume of water that it displaces, I would have to say that the scale would remain balanced.

Lu**********:

I was going ping pong first but I thought about the acrylic ball being slightly suspended in water because in water the greater the density difference the faster it sinks so because the acrylic ball's density isn't infinite the water does push up on the ball even if only slightly.This push upwards adds force to the water downwards. That should get u the answer but I'm not sure if the force exerted by the ping pong ball is greater. Because it is a trick question it most likely is acrylic or equal.

Si**********:

I only chose the acrylic option because it was the most logical guess.. if it was one of the other two answers.. it wouldn't have been as interesting.. so the set up gave it away.. though if there was no set up or video on why it's weird or interesting or different.. I would of thought one of the other two options would of happened.

Edit: I'm surprised by the people in the video, shouldn't they know that it's going to be an interesting unsuspecting not so obvious result.. so therefore you should go with the acrylic ball.. a 2nd grader could guess the same thing they did for the same reasons.. obviously there's something more to it.. I think people need to learn to read situations more..

xa*****:

I think the scale will stay balanced ( C ). Here's why: Consider a situation where an external agent (ex. Derek's hand), keeps a ping pong ball fixed in place in each of the 2 beakers. The scale would have to stay balanced, because the same thing is happening on both sides. Now, swap out one ping pong ball for a new, same-sized mystery ball, and let Derek keep it in place without it moving. As far as the water is concerned, the new ball is the same as the old one; it's still fixed in the same place, and it still displaces the same amount of water. Now let's say the mystery ball happens to be blue and acrylic, and instead of Derek holding it in place, a suspension cable does that work for him. Compared to the forcibly submerged ping pong ball, the acrylic ball still displaces the same amount of water. So in both cases, both balls exert the same buoyant force on the water, so they push the water down the same amount, so the resultant forces on each side of the scale must be equal.
Thanks for reading!

Ac********:

Okay, here's what I'm thinking (before watching): The acrylic ball is not adding any weight to the right side of the scale, because it is completely supported by the overhead apparatus.  The Ping-Pong ball, on the other hand... for a moment I thought it might provide lift to the left side of the scale, because it's floating... but no, the fact is, it's still adding mass, and the ping pong ball is still denser than AIR, which is what you're pushing against underneath the scale.  I say the Ping-Pong ball side will go down.

 

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[Veritasium] We gathered comments about popular videos and looked at them in summary, including play time, and order of popularity.

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